Constitutional isomers of C2H4O | Aldehyde & Ketone – Dr K
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Constitutional isomers of C2H4O | Aldehyde & Ketone – Dr K


The question is asking us to draw out
all possible aldehyde and ketones isomers for C2H4O. Aldehyde has a
carbonyl functional group which is C=O connected to a hydrogen.
Note that the carbonyl group in aldehyde is always at the first carbon,
whereas for ketone, it also has a carbonyl group but it is sandwiched
between two carbons, so, the difference between aldehyde and ketone is that they
both have carbonyl group but in aldehyde there’s a H connected next to it. In
ketone, both sides are carbon. So, let’s start with aldehyde. Since we only
have two carbons, let’s place them next to each other and then we’ll add in the
carbonyl group and hydrogen right next to the carbonyl carbon. Then we’ll fill
in the remaining bonds on carbon with hydrogens. Since carbon makes four bonds,
the carbon on the right will connect to three hydrogens like this. So, it looks
like we’ve completed our first isomer. There is no other way we can draw
aldehyde with two carbons, so, let’s see if we can draw any isomer for ketone. As
mentioned earlier, the functional group for ketone is carbonyl carbon and
sandwiched between two carbons like this. However, the formula that is given, C2H4O,
only has two carbons and in order to draw a ketone we need at least three
carbons, so, that means there’s no ketone for C2H4O. So, there is only one
structure for aldehyde and none for ketone for C2H4O. If you’re interested
in drawing other isomer aside from aldehyde and ketone for this
formula, let me know in the comments and I’ll post a video for it. I hope you find the video helpful. Do subscribe and thanks for watching!

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